17x^2-36x-460=0

Solution for 17x^2-36x-460=0 equation:

17x^2-36x-460=0

a = 17; b = -36; c = -460;
Δ = b2-4ac
Δ = -362-4·17·(-460)
Δ = 32576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32576}=\sqrt{64*509}=\sqrt{64}*\sqrt{509}=8\sqrt{509}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-8\sqrt{509}}{2*17}=\frac{36-8\sqrt{509}}{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+8\sqrt{509}}{2*17}=\frac{36+8\sqrt{509}}{34}
$